Calculate the address lines required for an 8k-byte(1024*8=8192 registers)
memory chip.
Answers
Answer:
The answer to the given question is:
11
Explanation:
11 address lines are required to address each machine location in the 2048 X 4 memory chip.
This means 2048 word memory, where each word is 4 bits. So to address 2048 (or 2K, where K means 2^10 or 1024) you need 11 bits, hence 11 address lines. In straightforward terms, without any multiplexing, the number of bits required to address memory is the number of lines (address or data) needed to access that memory. Quoting the Wikipedia article, a system with a 32-bit address bus can handle 232 (4,294,967,296) memory locations.
An address line refers to the physical connection between the processor and memory. It specifies which address to access in memory. For 'n' bitstream address we can access 2" memory locations.
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