calculate the ages of a mother and her two children. Knowing that the mother was 5 times the sum of the ages of her two children; that in 10 years, the age of the mother will be equal to the sum of the ages of her two children. when the eldest son is the age of the mother, the youngest son will be 42 years old??
Answers
Answer:
1
A mother's age is equal to the sum of the ages of her five children. If after 12 years, the sum of the ages of the children will be twice the age of their mother, how old is the mother now?
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Yash Sahu
Answered May 29, 2018
This shall be easy peasy…
Let the current age of mother be ‘X’ and let the ages of the five children be A, B, C, D and E.
Also let the sum of the current ages of the children be Y. ie
A+B+C+D+E = Y ~equation 1
The question clearly states that the current age of mother is equal to that of the sum of the current ages of the five children. So,
X = Y ~ equation 2
Now the mother's age after 12 years will be current age added 12. ie (X + 12)
Also the ages of the five children after 12 years will be (A+12), (B+12), (C+12), (D+12), (E+12).
Therefore the sum of all of the children's ages after 12 years will be :
A + 12 + B + 12 + C + 12 + D + 12 + E + 12
Which is equal to A+B+C+D+E+60
Using the equation 1, we can reduce the above to : (Y + 60)
The whole point of using A, B, C, D and E separately wa
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Padmini Kalyanaraman
Answered May 30, 2018
Let Mother's present age be ' x ' years.
let a,b,c,d,e,f be age of each daughter.
let the sum of the ages a+b+c+d+ e be 'y' years.
According to the statement of the sum
x= y ……..(1)
After 12 years mother's age =( x+12) years
After 5 years Daughter's age , a+12, b+12 , c+12, d+12,e+12
Their sum a+b+c+d+e + 60 =( y + 60)
According to the second statement of the sum
y+ 60 = 2(x+12)
x+ 60 = 2(x+12) [ where x= y from 1]
x+60 = 2x+ 24
x-2x= -60+24
-x= -36
x= 36
Mother's present age is 36 years
Ans : 36 years
this is the correct answer