Question

Calculate the amount 0of heat required to convert 1 kg of ice at -10 degree c into steam at 100 degree at normal pressure.

Answer 1

Heat required to conver 1kg of ice at -10 deg C to 1 kg water at 0 deg C

H = ms dT + mL

H = 1000(1/2)10 + 1000(80)

H = 5000+80000 = 85000 calories

Heat required to convert 1 kg water at 0 deg C to 1kg steam at 100 deg C

Q = ms dT + mL

Q = 1000(1)100 + 1000(540)

Q = 100000+540000

Q = 640000 calories

Total heat

h = Q + H

h = 725000

h = 725 kcal