Question

calculate the amount and compound interest of 10800 rupees for 3 years at 12½% per anum
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Answer 1

Given:-

P=10,800

n=3 years

Rate=$12\dfrac{1}{2}=\dfrac{25}{2}$

To find:-

Amount and compound interest

Solution:-

A=$\sf p(1+\dfrac{R}{100})^{n}$

$\sf\implies 10800(1+\dfrac{25}{100})^{3}$

$\sf\implies 10800(\dfrac{225}{100})^{3}$

$\sf\implies 10800×\dfrac{225}{100}×\dfrac{225}{100}×\dfrac{225}{100}$

$\sf\therefore A=15377.34Rs$

$\sf Compound \:Interest=Amount-P\\ \sf =15377.34−10,800\\ \sf =4577.34Rs$