Calculate the amount and compound interest of Rs 4600 in 2 years when the rate of interest of successive years are 10 % and 20 % respectively (solve it without using formula)
Solve it fast its urgent plz
Answers
Solution!!
The concept of compound interest has to be used here.
First year:-
Principal (P) = Rs 4600
Time (T) = 1 year
Rate of interest (R) = 10%
Interest = (P × R × T)/100
Interest = (4600 × 10 × 1)/100
Interest = 46 × 10 × 1
Interest = Rs 460
Amount = Principal + Interest
Amount = Rs 4600 + Rs 460
Amount = Rs 5060
Second year:-
The amount in the first year becomes principal in the second year.
Principal (P) = Rs 5060
Time (T) = 1 year
Rate of interest (R) = 20%
Interest = (P × R × T)/100
Interest = (5060 × 20 × 1)/100
Interest = 506 × 2 × 1
Interest = Rs 1012
Amount = Principal + Interest
Amount = Rs 5060 + Rs 1012
Amount = Rs 6072
Compound Interest (CI) = Final amount - Principal in the first year
CI = Rs 6072 - Rs 4600
CI = Rs 1472
Answer:
● Calculate the amount and compound interest of Rs 4600 in 2 years when the rate of interest of successive years are 10 % and 20 % respectively..
- Substituting the values
- Hence, The Amount is Rs.6072
- Substituting the values
- Henceforth,The Compound Interest is Rs.1472.
- ● The Amount is Rs.6072.
- ● The Compound Interest is Rs.1472.
★ Formula of Principle(P) if Amount and Interest given
★ Formula of Principle (P) if Interest,time and rate given
★ Formula of Principle (P) if amount,time and rate given
★ Formula of Amount if Principle (P) and Interest (I) given