Calculate the amount and compound interest on 16000 for 2years compounded annually the rate of interest being 9% per annum in first year and 10% per annum in second year
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Principal (p1) = 16000
Time (t) = 2 years
Rate in 1st year (r1) = 9%
Rate in 2nd year (r2)= 10%
C.I1 in 1st year:
(p1*r1*1)/100
= (16000*9*1)/100
= 1440
Amount in 1st year = p1 + C.I1
= 16000 + 1440
= 17440
principal(p2) in 2nd year is equal to amount in 1st year
=> p2 = 17440
C.I (C.I2)in 2nd year:
= (p2*r2*1)/100
= (17440*10)/100
= 1744
Amount = p2+C.I2
= 17440+1744
= 19184
Total C.I = C.I1+C.I2
= 1440+1744
= 3184
Answer:
Amount = 19184
C.I = 3184
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