Math, asked by kalpana2016nigam, 8 months ago

Calculate the Amount and Compound Interest on Rs 10,800 for 3 years at 12.5%
per annum​

Answers

Answered by 526526
2

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Answer:

Principal (P) = Rs 10, 800

Rate (R) 12 1/2% = 25/2% ( annual )

Number of years (n) = 3 Amount,

A = p( 1 + R/100 )n = Rs [10800 (1 + 25/200)3]

                               = Rs [10800(225/200)3]

                               = Rs ( 10800 x 225/200 x 225/200 x 225/200 )

                               = Rs 15377.34375 = Rs 15377.34  (approximately)

C.I. = A − P = Rs (15377.34 − 10800)

                   = Rs 4,577.34

Principal (P) = Rs 18,000

 Rate (R) = 10% annual

Number of years (n) = 2 1/2 years

The amount for 2 years and 6 months can be calculated by first calculating the amount for 2 years using the compound interest formula, and then calculating the simple interest for 6 months on the amount obtained at the end of 2 years. Firstly, the amount for 2 years has to be calculated.

A = Rs [18000( 1 + 1/10 )2]

    = Rs (18000 x 11/10 x 11/10)

    = Rs 21780

By taking Rs 21780 as principal, the S.I. for the next 1/2 year will be calculated.

S.I = Rs (21780 x 1/2 x 10 / 100)

    = Rs 1089 ∴ Interest for the first 2 years

    = Rs (21780 − 18000) = Rs 3780

And interest for the next 1/2 year = Rs 1089

∴ Total C.I. = Rs 3780 + Rs 1089 = Rs 4,869 A = P + C.I. = Rs 18000 + Rs 4869

                         Total C.I = Rs 22,869

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