Calculate the Amount and Compound Interest on Rs 10,800 for 3 years at 12.5%
per annum
Answers
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Answer:
Principal (P) = Rs 10, 800
Rate (R) 12 1/2% = 25/2% ( annual )
Number of years (n) = 3 Amount,
A = p( 1 + R/100 )n = Rs [10800 (1 + 25/200)3]
= Rs [10800(225/200)3]
= Rs ( 10800 x 225/200 x 225/200 x 225/200 )
= Rs 15377.34375 = Rs 15377.34 (approximately)
C.I. = A − P = Rs (15377.34 − 10800)
= Rs 4,577.34
Principal (P) = Rs 18,000
Rate (R) = 10% annual
Number of years (n) = 2 1/2 years
The amount for 2 years and 6 months can be calculated by first calculating the amount for 2 years using the compound interest formula, and then calculating the simple interest for 6 months on the amount obtained at the end of 2 years. Firstly, the amount for 2 years has to be calculated.
A = Rs [18000( 1 + 1/10 )2]
= Rs (18000 x 11/10 x 11/10)
= Rs 21780
By taking Rs 21780 as principal, the S.I. for the next 1/2 year will be calculated.
S.I = Rs (21780 x 1/2 x 10 / 100)
= Rs 1089 ∴ Interest for the first 2 years
= Rs (21780 − 18000) = Rs 3780
And interest for the next 1/2 year = Rs 1089
∴ Total C.I. = Rs 3780 + Rs 1089 = Rs 4,869 A = P + C.I. = Rs 18000 + Rs 4869
Total C.I = Rs 22,869