Question

Calculate the amount and compound interest on rs.10800 for 3 year's at 12.5% per annum compound anually​.​

Answer 1

Answer:

given, P = 10,800 Rs. T = 3 years and R = 12 1/2 % = 25/2 % per annum

use formula,

A=P\left(1+\frac{R}{100}\right)^TA=P(1+

100

R

)

T

or, A=10800\left(1+\frac{\frac{25}{2}}{100}\right)^3A=10800(1+

100

2

25

)

3

or, A=10800\left(1+\frac{25}{200}\right)^3A=10800(1+

200

25

)

3

or, A=10800\left(1+\frac{1}{8}\right)^3A=10800(1+

8

1

)

3

or, A=10800\left(\frac{9}{8}\right)^3A=10800(

8

9

)

3

or, A = 10800 × 9 × 9 × 9/(8 × 8 × 8)

= 15,377.3438 Rs.

now, compound interest = A - P

= 15,377.3438 - 10,800

= 4,577.3438 Rs.

Answer 2

Given :-

• Principal = 10800 ₹
• Time = 3 years
• Rate = 12.5 % per annum compounded annually.

Answer :-

• Compound interest = 4577 ₹

To Find :-

• Find the amount and the compound interest.

Explanation :-

As we know,

$\blue{\boxed{\bf \bigstar \: Compound \: Interest = P \: (\dfrac{1 + R}{100})^T \: \bigstar}}$

$\sf\longmapsto \: A = 10800 \times { ( \dfrac { 1 + 12.5 } { 100 } ) }^{ 3 }$

$\sf\longmapsto \: A = 10800 \times {1.125 }^{ 3 }$

$\sf\longmapsto \: A = 15377$

Now, We have to find the compound Interest

$\sf\longmapsto \: Interest = 15377 - 10800$

$\red{\underline{\boxed{\bf\longmapsto \: Interest = 4577 \qquad \star}}}$

Hence, Compound interest is 4577 ₹