Question

Calculate the amount and compound interest on Rs. 20000 in 2 years at 25% per annum compounded annually.

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Answer 1

Given :

• Principal (P) = Rs. 20000
• No. of Years (n)= 2 years
• Rate of Interest (r) = 25%

To Find :

• Amount and Compond Interest .

Solution :

Firstly we will find Amount :

Using Formula :

$\longmapsto\tt\boxed{Amount=P\bigg(1+\dfrac{r}{100}\bigg)^{n}}$

Putting Values :

$\longmapsto\tt{20000\bigg(\dfrac{1}{1}+\dfrac{25}{100}\bigg)^{2}}$

$\longmapsto\tt{20000\bigg(\dfrac{100+25}{100}\bigg)^{2}}$

$\longmapsto\tt{20000\bigg(\cancel\dfrac{125}{100}\bigg)^{2}}$

$\longmapsto\tt{20000\bigg(\dfrac{5}{4}\bigg)^{2}}$

$\longmapsto\tt{{\cancel{20000}}\bigg(\dfrac{25}{{\cancel{16}}}\bigg)}$

$\longmapsto\tt{1250(25)}$

$\longmapsto\tt\bf{Rs.31250}$

So , The Amount is 31250 ....

Now ,

$\longmapsto\tt{C.I=Amount-Principal}$

$\longmapsto\tt{31250-20000}$

$\longmapsto\tt\bf{Rs.11250}$

So , The Compound Interest is Rs. 11250 ...

Answer 2

Answer:

${\huge{\pink{\underline{GiVeN}}}}$

• Principal(p)=20000
• Time(n)=2yrs
• Rate of interest(r) =25percent

${\huge{\pink{\underline{To\ FiNd:}}}}$

• Amount=???
• Compound interest=???

${\huge{\pink{\underline{Formula\ used:}}}}$

• $Amount=P{(1+(r/100))}^{n}$
• C.P.=Amount-Principal

${\huge{\pink{\underline{SoLuTiOn:}}}}$

$Amount=20000{(1+(25/100))}^{2}\\</p><p> =20000{(1+(1/4))}^{2}\\</p><p> =20000×5/4×5/4\\</p><p> =(200000×5)/16\\</p><p> =100000/16\\</p><p> =25000$

Compound interest=25000-20000

=rs.5000