Question

calculate the amount and compound interest on rs10000 for three years at 6% per anum compound anually​

Answer 1

A = p(1+r/100)^t

= 10000(1+6/100)³

= 10000(106/100)³

= 10000(106/100)(106/100)(106/100)

= 10000(53/50)(53/50)(53/50)

= 11,910.16

Amount = 11910.16

C.I = (Amount - Principal) = 1910.16

Answer 2

Step-by-step explanation:

Given:-

• Principal (P) = Rs.10000

• Rate (r) = 6%

• Time (n) = 3 years

To Find:-

• The Amount

• Compound Interest compounded annually.

Solution:-

The formula for finding Amount is:-

$\boxed{\bf Amount = P\bigg(1 + \dfrac{r}{100}\bigg)^{n}}$

Here:-

• P = Rs.10000 , r = 6% and n = 3 years

Substituting the values:-

$\dashrightarrow\sf A = 10000\times \bigg(1 + \dfrac{6}{100}\bigg)^{3}$

$\dashrightarrow\sf A = 10000\times \bigg( \dfrac{100 + 6}{100}\bigg)^{3}$

$\dashrightarrow\sf A = 10000\bigg( \dfrac{106}\times {100}\bigg)^{3}$

$\dashrightarrow\sf A = 10000 \times \dfrac{106 \times 106 \times 106}{100 \times 100 \times 100}$

$\dashrightarrow\sf A = 10000 \times \dfrac{1191016}{1000000 }$

$\dashrightarrow\sf A = \dfrac{1191016}{100}$

$\dashrightarrow\sf A = 11910.16$

$\dashrightarrow\sf \underline{ \: \: \underline{ \: \: \pink{ Amount= Rs.11910.16} \: \: } \: \: }$

$\sf Now,\: Let \:us\: find \:Compound\: Interest\: (CI):-$

$\boxed{\bf CI = Amount - Principal}$

$\sf \dashrightarrow CI = 11910.16 - 10000$

$\sf \dashrightarrow CI = 1910.16$

$\underline{\boxed{ \therefore \purple{\textsf{ \textbf{Compound \: interest = Rs.1910.16}}}}}$