Question

Calculate the amount and compound interest on
rupees 10,000 in 2 years at 10% per year.​

Answer 1

Answer:

answer =₹12100

Step-by-step explanation:

10,000*1+10/100*1+10/100

10,000*110/100*110/100

10,000*11/10*11/10

100*11*11

12100

Answer 2

Answer:

p = 10000rs,

r = 10% = 10/100 = 0.1,

n = 1 (once yearly),

t = 2 years,

a =?

Now,

a = p(1 +  \frac{r}{n} )^{n \times t }  

=10000(1 +  \frac{0.1}{1} )^{1 \times 2}  

= 10000(1 + 0.1)^{2}  

= 10000(1.1)^{2}  

= 10000 \times 1.21

= 12100rs

Therefore,

Compound Interest would be 12100rs.

Step-by-step explanation:

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