Question

calculate the amount and compound interest on rupees 10000 rate 5% time 2 years compounded annually
pls answer fast
will be a brainlist​

Answer 1

Step-by-step explanation:

Compound interest,

[10000 X 5 X 2]/100

=100 X 5 X 2

=1000

Amount=1000

10000-1000=9000

Simple interest=9000

Answer 2

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• ➙ Principle = Rs.10000
• ➙ Rate = 5 %
• ➙ Time = 2 years
• ➙ Compounded = Annually

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• ➙ Compound Interest = ?

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✧ Formula Used :

$\large{\blue{\dag}}{\underline{\boxed{\orange{\sf{ C.I = P\bigg[1 + \dfrac{R}{100}\bigg]^T - P }}}}}{\blue{\dag}}$

⧪ Here :

• ➳ C.I = Compound Interest = ?
• ➳ P = Principle = Rs.10000
• ➳ R = Rate = 5 %
• ➳ T = Time = 2 years

$\qquad{━━━━━━━━━━━━━━━━━━━━━━}$

✧ Finding the Compound Interest :

$\qquad{:\implies{\sf{ C.I = P \bigg[1 + \dfrac{R}{100} \bigg]^T - P}}}$

$\qquad{:\implies{\sf{ C.I = 10000 \bigg[1 + \dfrac{5}{100} \bigg]^2 - 10000}}}$

$\qquad{:\implies{\sf{ C.I = 10000 \bigg[1 + \cancel\dfrac{5}{100} \bigg]^2 - 10000}}}$

$\qquad{:\implies{\sf{ C.I = 10000 \bigg[1 + 0.05 \bigg]^2 - 10000}}}$

$\qquad{:\implies{\sf{ C.I = 10000 \bigg[1.05 \bigg]^2 - 10000}}}$

$\qquad{:\implies{\sf{ C.I = 10000 \times 1.1025 - 10000}}}$

$\qquad{:\implies{\sf{ C.I = 11025 - 10000}}}$

$\qquad{\large{\purple{\dashrightarrow\underline{\boxed{\pink{\sf{C.I {\blue{\sf{ \: = {\color{maroon}{\sf{ Rs.1025}}}}}}}}}}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━━}$

✧ Therefore :

❝ Compound interest is Rs.1025 . ❞

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