Question

calculate the amount and compound interest on the 8000 at 10 % for 3 years​

Answer 1

Given :

• Principal (P) = Rs 8000
• Time (n) = 3 years
• Rate (R) = 10% per annum

To Find :

• Compound interest

Formulas :

$\red \bigstar \: {\underline{\boxed{\mathcal {\pmb{\quad Amount \: = \: Principal \: \times \bigg(\:1 \: + \: \dfrac{Rate}{100}\bigg)^{n}\quad}}}}}$

$\red \bigstar \: {\underline{\boxed{\mathcal {\pmb{\quad Compound \: Interest \: = \: Amount \: - \: Principal \quad}}}}}$

Solution :

${:} \longrightarrow \sf \: Amount \: = \: Principal \: \times \bigg(\:1 \: + \: \dfrac{Rate}{100}\bigg)^{n} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 8000 \: \times \bigg(\:1 \: + \: \dfrac{10}{100}\bigg)^{3} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 8000 \: \times \bigg(\dfrac{110}{100}\bigg)^{3} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 8000\: \times \: \dfrac{110}{100} \: \times \: \dfrac{110}{100} \: \times \: \dfrac{110}{100} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: 8\cancel{000} \: \times \: \dfrac{110}{1 \cancel{00}} \: \times \: \dfrac{110}{10 \cancel{0}} \: \times \: \dfrac{110}{100} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: \dfrac{8 \: \times \: 110 \: \times \: 110 \: \times \: 110}{10 \: \times \: 100} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: \dfrac{880 \: \times \: 12100}{ 1000} \\ \\ {:} \longrightarrow \sf \: Amount \: = \: \dfrac{10648000}{ 1000} \\ \\ {:} \longrightarrow \underline{\boxed{\sf \: Amount \: = \: Rs \: 10648}} \: \blue \bigstar$

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$\longmapsto {\pmb{ Compound \: Interest \: = \: Amount \: - \: Principal} } \\ \\ \longmapsto {\sf{ Compound \: Interest \: = \: 10648 \: - \: 8000} } \\ \\ \longmapsto \underline{\boxed{\pmb{ \red{ Compound \: Interest \: = \:Rs \:2,648} }}}$

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$\qquad \therefore\: \sf{ Amount \: = \underline {\underline{ Rs \: 10648}}}$

$\qquad \therefore\: \sf{ Compound \: Interest\: = \underline {\underline{ Rs \: 2,648}}}$

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Answer 2

Given :

• Principal (P) = 8000
• Rate of interest (R) = 10%
• Time (n) = 3 years

To find :

• Amount and compound interest

Solution :

• In the question Principal, rate of intrerst and time is given. Firstly we will find the amount and then the compound interest.

Amount = P (1 + R/100)ⁿ

➤ 8000 ( 1 + 10/100)³

➤ 8000 × 11/10 × 11/10 × 11/10

➤ 8 × 11 × 11 × 11

➤ Rs.10,648

Required Amount is Rs.10,648

____________

C.I = Amount - Principal

➤ 10,648 - 8000

➤ Rs. 2,648

Required C.I is Rs. 2,648.

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