Question

calculate the amount and compound interset on ₹15,000for 2 years at the rate of 12%per annum compouned annually​

Answer 1

Answer:

3600

Step-by-step explanation:

A= (p×r×t/100)+p

A= (15000×12×2/100) + 15000

A= (150×12×2)+15000

A=3600+15000

A=18600

CI=A-P

CI=18600-15000

CI=3600

Answer 2

⇒ Given:

Principal amount = ₹15,000

Rate of interest = 12%

Time period = 2 years

Mode of compounding = Annually

⇒ To Find:

The amount and compound interest at the end of 2 years.

⇒ Solution:

Formula to find The amount when Principal is compounded annually:

$\sf{\implies\:Amount=P(1+\dfrac{R}{100})^n}$

Here,

P = 15000

R = 12%

n = 2

Substituting the values into the equation:

$\sf{\longrightarrow\:Amount=15000(1+\dfrac{12}{100})^2}$

$\sf{\longrightarrow\:Amount=15000(1+\dfrac{3}{25})^2}$

$\sf{\longrightarrow\:Amount=15000\times\dfrac{28}{25}\times\dfrac{28}{25}}$

$\sf{\longrightarrow\:Amount=24\times28\times28}$

$\bf{\longrightarrow\:Amount=Rs.18816}$

The next formula to be used is:

$\sf{\implies\:C.I=Amount-Principal}$

Amount = Rs.18816

Principal = Rs.15000

Substituting the values into the equation:

$\sf{\longrightarrow\:C.I=18816-15000}$

$\bf{\longrightarrow\:C.I=Rs.3186}$

⇒ Final answers:

✳ Amount = Rs.18816

✳ Compound interest = Rs.3186