Question

calculate the amount and compound intrest on rs 10000 at 8%per anumin 2 year

Answer 1

Amount = Rs. 11667

Compound Interest = Rs. 1664

• SOLUTION:

Given:

• Principal (P) = Rs. 10000
• Rate of Interest (R%) = 8% p.a.
• Time (n) = 2 years

To find:

Amount (A), and Compound Interest (C.I)

• The formula to find the Amount (A) is

A = P [1 + (R/100)ⁿ ]

A = 10000 [1 + (8/100)² ]

A = 10000 [1 + (2/25)² ]

A = 10000 * [ (25+2)/25 ]²

A = 10000 * (27/25)²

A = 10000 * (729/625)

A = 16 * 729

Amount (A) = Rs. 11664

Now,

• The formula to find the Compount Interest(C.I)

C.I = P [ (1 + {R/100} )ⁿ - 1]

C.I = 10000 [ (1 + {8/100} )² - 1]

C.I = 10000 [ (1 + {2/25} )² - 1]

C.I = 10000 [ (27/25)² - 1]

C.I = 10000 [ (729/625) - 1]

C.I = 10000 * (729 - 625)/625

C.I = 10000 * (104)/625

C.I = 16 * (104)

Compound Interest (C.I) = Rs. 1664

Answer 2

Answer:

☞ Given :-

Principal (P) = 10000

Rate (R) = 5%

Time (T) = 2 years

☞ To Find :-

Amount (A) and Compound Interest (CI)

☞ Solution :-

We know that,

Amount(A) =

$\sf{P \times {(1 + \frac{R}{100}) }^{n}}</p><p>$

Here,

A = Amount

n = number of years

P = Principal

R = Rate

So,

By putting the above values in it, we get,

$\green{\begin{gathered} \sf\implies \: A = 10000 \sf\times {(1 + \frac{5}{100} )}^{2} \\ \\ \implies \: A = 10000 \times {(1 + 0.05)}^{2} \\ \\ \implies \: A \: = 10000 \times {(1.05)}^{2} \\ \\ \ \\ \implies \: A \: = 10000 \times 1.1025 = 11025\end{gathered}}</p><p>$

So,

Amount (A) = 11025

We know that,

Interest = Amount (A) - Principal (P)

So,

Interest = 11025 - 10000 = 1025