Question

calculate the amount and the compound interest by using the formula for compound interest
principal=625 ratep.a.=4% time (in years)=2
please solve In copy and send fast​

Answer 1

Answer:

• Amount is 676.
• Compound interest is 51.

Step-by-step explanation:

Given :-

• Principal is 625.
• Rate of interest is 4%.
• Time period is 2 years.

To find :-

• Amount.
• Compound interest.

Solution :-

We know,

$\boxed{\sf \bold{Amount = P \bigg(1 + \dfrac{r}{100}\bigg)^{n}}}$

Where,

• P is principal, r is rate of interest and t is time period.

Put all values,

$\sf \longrightarrow Amount = 625 \times \bigg( 1 + \dfrac{4}{100} \bigg)^{2}$

$\sf \longrightarrow Amount = 625 \times \bigg( \dfrac{100 + 4}{100} \bigg)^{2}$

$\sf \longrightarrow Amount = 625 \times \bigg( \dfrac{104}{100} \bigg) ^{2}$

$\sf \longrightarrow Amount = 625 \times \dfrac{10816}{10000}$

$\sf \longrightarrow Amount = 625 \times 1.0816$

$\longrightarrow \purple{\boxed{\sf \bold{ Amount = 676}}\star}$

Thus,

Amount is 676

Now,

$\boxed{\sf \bold{Compound \: interest = Amount - Principal}}$

$\sf \longrightarrow 676 - 625$

$\longrightarrow \red{\boxed{\sf \bold{51}}\star}$

Therefore,

Compound interest is 51.

Answer 2

${\Large{\bold{\rm{\underline{Understanding \: the \: question}}}}}$

This question says that we have to find the amount and the compound interest. Now it's given that principal = 625 , rate p.a. = 4% , time (in years)= 2

$\sf Given \: that \begin{cases} & \sf{Principal = \bf{625 \: Rupees}} \\ & \sf{Rate \: per \: annum = \bf{4 \: \%}} \\ & \sf{Time =\bf{2 \: years}} \end{cases}$

$\sf To \: find \begin{cases} & \sf{Amount} \\ & \sf{Compound \: interest} \end{cases}$

$\sf Solution \begin{cases} & \sf{Amount = \bf{676 \: Rupees}} \\ & \sf{Compound \: interest = \bf{51 \: Rupees}} \end{cases}$

$\sf Using \: concepts \begin{cases} & \sf{Formula \: to \: find \: amount} \\ & \sf{Compound \: interest \: formula} \end{cases}$

$\sf Using \: formulas \begin{cases} & \sf{Amount = \bf{P(1+r/100)^{n}}} \\ & \sf{Compound \: interest = \bf{Amount \: - \: Principal}} \end{cases}$

$\sf We \: also \: write \: these \: as \begin{cases} & \sf{Amount \: as \: \bf{A}} \\ & \sf{Compound \: interest \: as \: \bf{CI}} \\ & \sf{Principal \: as \: \bf{P}} \\ & \sf{Time \: as \: \bf{t}} \\ & \sf{n \: denotes \: \bf{time}} \\ & \sf{Rate \: of \: interest \: as \: \bf{r}} \end{cases}$

${\Large{\bold{\rm{\underline{Full \: solution}}}}}$

~ Finding Amount

➥ P(1+r/100)ⁿ

➥ 625(1+4/100)²

• Taking Lcm of 1 and 100 we get 100. Now,

➥ 625(100+4/100)²

➥ 625(104/100)²

➥ 625(10816/10000)

➥ 625(1.0816)

➥ 625 × 1.0816

➥ 676 Rupees

• Henceforth, 676 Rupees is the amount

~ Finding Compound Interest

➥ Amount - Principal

➥ 676 - 625

➥ 51 Rupees

• Hence, 51 Rupees is Compound Interest.

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