Question

. Calculate the amount and the compound interest to the nearest rupee on 42000 for 2 years at 8
% per annum, interest being payable half-yearly.​

Answer 1

Step-by-step explanation:

(1) Here, P = ₹ 2000; R = 5 % ; N = 2 years

A=P(1+R100)N =2000(1+5100)2 =2000(105100)2 =2000(2120)2 =2205 Rupees∴ Compound Interest after 2 years,I = Amount − Principal =2205−2000 =205 Rupees

Hence, Amount = ₹ 2205 and Compound interest = ₹ 205.

(2) Here, P = ₹ 5000; R = 8 % ; N = 3 years

A=P(1+R100)N =5000(1+8100)3 =5000(108100)3 =5000(2725)3 =6298.56 Rupees∴ Compound Interest after 3 years,I = Amount − Principal =6298.56−5000 =1298.56 Rupees

Hence, Amount = ₹ 6298.56 and Compound interest = ₹ 1298.56

(3) Here, P = ₹ 4000; R = 7.5 % ; N = 2 years

A=P(1+R100)N =4000(1+7.5100)2 =4000(1+751000)2 =4000(10751000)2 =4000(4340)2 =4622.50 Rupees∴ Compound Interest after 2 years,I = Amount − Principal =4622.50−4000 =622.50 Rupees

Hence, Amount = ₹ 4622.50 and Compound interest = ₹ 622.50