Question

calculate the amount if Rs 6000 invested at 5%p.a . compunded annually time 2 year​

Answer 1

Answer:

The amount calculated is ₹6, 615

Step-by-step explanation:

Given :

• principal = ₹6,000
• rate = 5% p. a.
• Time = 2 years.

Finding the amount

We know that,

${ \underline{ \boxed{\sf Amount = p\bigg(1 + \dfrac{r}{100}\bigg)^n}}}$

Where,

• ‘n’ denotes the time i.e., 2 years.
• ‘p’ is the principal i.e., ₹6,000
• ‘r’ is the rate i.e., 5% p. a. (per annum)

Calculating the amount :

${ { {\sf Amount = p\bigg(1 + \dfrac{r}{100}\bigg)^n}}}$

$\sf \to 6000 \bigg (1 + \frac{5}{100} \bigg)^{2}$

$\sf \to 6000 \bigg(1 + \frac{1}{20} \bigg)^{2}$

$\sf \to 6000 \bigg( \frac{21}{20} \bigg)^{2}$

$\sf \to 6000 \times \frac{441}{400}$

$\sf \to 15 \times 441$

$\sf \to \: 6615$

The amount is ₹6,615

Answer 2

$\large{ \textsf{ \textbf{ \color{lightgreen}{Step}}}}{ \textsf{ \textbf{ \color{mediumaquamarine}{-by-}}}}{ \textsf{ \textbf{ \green{step}}}}{ \textsf{ \textbf{ \color{green}{ explanation }}}}{ \color{darkgreen}{ : }}$

Given :

• Principal = ₹6,000
• Rate = 5% p. a.
• Time = 2 years.

Finding the amount :

We know that,

${ \blue{ \boxed{\sf Amount = p\bigg(1 + \dfrac{r}{100}\bigg)^n}}}$

Where,

• ‘n’ denotes the time i.e., 2 years.
• ‘p’ is the principal i.e., ₹6,000
• ‘r’ is the rate i.e., 5% p. a. (per annum)

Calculating the amount :

${ \blue{ \sf{Amount = p\bigg(1 + \dfrac{r}{100}\bigg)^n}}}$

$\sf \leadsto6000 \bigg (1 + \frac{5}{100} \bigg)^{2}$

$\sf \leadsto6000 \bigg(1 + \frac{1}{20} \bigg)^{2}$

$\sf \leadsto 6000 \bigg( \frac{21}{20} \bigg)^{2}$

$\sf \leadsto 6000 \times \frac{441}{400}$

$\sf \leadsto 15 \times 441$

$\sf \leadsto{ \red{ 6615}}$

$\sf{ \underline{ \pink{The  \: amount  \: calculated \: is  \: ₹6,615}}}$