Question

Calculate the amount (in mol) of hydrochloric acid, HCl (aq), in 50.0 cm3 of a 2.00 mol dm-3 solution of HCl.

Answer 1

Answer:

0.1

Explanation:

1 dm3 = 1 litre ...... n is no. of moles

Answer 2

Answer:

0.1 moles

Explanation:

HCl= 50 cm³

Molar mass = 1 + 35.5 = 36.5

$molarity = \frac{number \: of \: moles}{volume \: of \: solution}$

= 50 × 2

1000

= 1

10

= 0.1 moles