Question

Calculate the amount in moles of S03 formed when 0.36mol S02 reacts
with excess 0 2.
2S02 + 0 2 -+ 2S03

Answer 1

Explanation:

calculate the amount in moles of SO3 formed when 0.36 mol SO2 reacts with excess O2.

2 SO2 + O2 --> 2 SO3