Question

Calculate the amount in moles of SO3 formed when 0.36 mol SO2 react with excess O2​

Answer 1

Answer:

0.36 moles of sulphur trioxide formed

Explanation:

2SO2 + O2 ---------> 2 SO3 . From this balanced chemical equation it is clear that 2 moles of sulphur dioxide gives 2 moles of sulphur trioxide. So 0.36 mol of sulphur dioxide will give 0.36 mol of sulphur trioxide.