Question

Calculate the amount of 18000 at 10%p.a. in 2 years

Answer 1

Answer:

Principal = Rs. 18000

Rate of interest = 10 %

Number of years = 2

Amount = P ( 1 + R/100 )^N

Amount = 18000 (1 + 10/100)²

Amount = 18000 × 110/100 × 110/100

Amount = 21,780

Therefore, amount will be Rs. 21780

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Answer 2

Principal = ₹ 18000

Rate of Interest = 10% p.a

Time = 2 yrs

$a = p(1 + { \frac{r}{100} )}^{2} \\ \\ = 18000(1 + { \frac{10}{100} )}^{2} \\ \\ = 18000(1 + { \frac{1}{10} )}^{2} \\ \\ = 18000 { (\frac{11}{10}) }^{2} \\ \\ = 18000 \times \frac{11}{10} \times \frac{11}{10} \\ \\ = 180 \times 121 \\ = 21780$

Amount = ₹ 21780

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