Question

Calculate the amount of ₹31250 at the end of 2 1/2 years, compounded annually at 8% per
annum​ please do using simple formula and subscribe my yt channel i will follow and thank you my yt channel name Legend GAMER Krish​

Answer 1

Question :–

• Calculate the amount of ₹31250 at the end of 2½ years, compounded annually at 8% per annum .

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ANSWER :–

GIVEN :–

• Principal = ₹31250

• Rate = 8%

• Time = 2½ year

TO FIND :–

• Amount = ?

SOLUTION :–

• We know that –

$\\ \large \star \: \: { \red{ \boxed{ \bold{Amount \: \: = \: \: P {(1 + \dfrac{R}{100} )}^{n} (1 + \dfrac{Fractional \: \: time \times R}{100} )}}}}$

• Here –

$\\ \: \: \: \: { \huge{.}}{ \blue{ \bold{ \: \: \: \: p = principal}}}$

$\\ \: \: \: \: { \huge{.}}{ \blue{ \bold{ \: \: \: \: R = Rate}}}$

$\\ \: \: \: \: { \huge{.}}{ \blue{ \bold{ \: \: \: \: n = time }}}$

• Now put the values –

$\\ \implies { \bold{A\: \: = \: \: 31250 {(1 + \dfrac{8}{100} )}^{ 2 } (1 + \dfrac{ \frac{1}{2} \times 8 }{100} )}}$

$\\ \implies { \bold{A\: \: = \: \: 31250 {( \dfrac{108}{100} )}^{ 2 } (1 + \frac{4}{100} )}}$

$\\ \implies { \bold{A\: \: = \: \: 31250 {( 1.08 )}^{ 2} ( \frac{104}{100} )}}$

$\\ \implies { \bold{A\: \: = \: \: 31250 {( 1.08 )}^{ 2} (1.04)}}$

$\\ \implies { \bold{A\: \: = \: \: 31250 \times 1.1664 \times 1.04}}$

$\\ \implies { \bold{A\: \: = \: \: 31250 \times 1.213056}}$

$\\ \implies \large { \pink{ \boxed{ \bold{A\: \: = \: 37908\: }}}}$

Hence , Amount is 37,908 ₹

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Answer 2

$\large\bf\underline \orange{Given:-}$

• Principal = ₹ 31250
• Rate = 8%
• Time = 2_1/2

$\large\bf\underline \orange{To \: find:-}$

• Amount

$\huge\bf\underline \green{Solution:-}$

$\bf\blue{\: Amount=p(1+\frac{R}{100})(1+\frac{Fractional\:time\times\:R}{100})} \\ \\ \longmapsto \rm \: 31250( \frac{108}{100} \times \frac{108}{100})( \frac{104}{100} ) \\ \\\longmapsto \rm \:31250( \frac{11664}{10000} )( \frac{104}{100}) \\ \\ \longmapsto \rm \:31250( \frac{1213056}{1000000} ) \\ \\\longmapsto \rm \:31250 \times 1.213056 \\ \\ \longmapsto \bf\: 37908$