Calculate the amount of 90% h2so4 required for the preparation of 420 kg of hcl
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I am using the method of preparation with Sodium chloride.
Reaction: NaCl + H₂SO₄ ------> NaHSO₄ + HCl (Temperature should be less than 200°C).
Now, Atomic mass of
H = 1
S = 32
O = 16
Cl = 35.5
Hence, molecular mass of sulphuric acid (H₂SO₄)
= 2x1 + 32 + 4x16
= 98
Again, molecular mass of hydrochloric acid (HCl)
= 1 + 35.5
= 36.5
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