Question

Calculate the amount of AgNO3 which should be
added to 120 mL of solution to prepare a
concentration of 0.03 g ml
(1) 3.6 g
(2) 3.6 mg
(3) 0.036 g
(4) 0.036 mg

if answer can be calculated with the help of formula of molarity please give the explaination​

Answer 1

Answer: The correct answer is Option 1.

Explanation:

We are given:

Concentration of silver nitrate = 0.03 g/mL

We need to find the amount of silver nitrate that is present in 120 mL of solution.

Using unitary method, we get:

1 mL of solution contains 0.03 grams of silver nitrate.

So, 120 mL of solution will contain = $\frac{0.03g}{1mL}\times 120=3.6g=3600mg$ of silver nitrate.

Conversion factor used:

1 g = 1000 mg

Hence, the correct answer is Option 1.