Question

Calculate the amount of air and volume of air required for complete combustion of 5kg of coal having the composition is C%= 84, H%= 10,S=2% and rest is ash.​

Answer 1

Explanation:

Solution : C + O2 CO2 C = 85% = 0.85 kg

12 + 32 44 H = 10% = 0.10 kg H2 +1/2O2 H2O 5% = 0.05 kg 5% = 0.05 kg 2 + 16 18 Element = weight in kg | Weight of O2 required for complete combustion in kg | |------------------------|-----------------------------------------------------| | C = 0.85 | 0.85 x 32/12 = 2.26 | | H =0.1 | 0.1 x 8 =0.8 kg | | O = 0.05 | - | | | Total oxygen = 3.06 kg |

Wt. of oxygen = wt. of oxygen needed – wt. of oxygen present = 3.06 – 0.05 = 3.01 kg Wt. of air required for complete combustion = [Air contains 23%O2 by weight] 3.01 x 100/23 = 13.08 kg per 1 kg of coal Air required for 5 kg of coal =13.08 x 5 = 65.40 kg Volume of air 28.94 kg of air = 22,400 ml volume at NTP 65.4kg of air = 22400 x 65.4/28.94 = 50620.6 ml of air Answer: Weight of air required= 65.40 kg Volume of air= 50620.6 ml of air