Question

Calculate the amount of aluminium required getting 1120 gms
of iron by the given reaction. The atomic mass elements
AI=27U, Fe=56U and O= 160. Al + Fe,O, AI,O, + Fe
PETO​

Answer 1

given chemical reaction is ..

2Al + Fe2O3 ⇔Al2O3 + 2Fe

here it is clear that , 2 moles of Aluminium produces 2 moles of iron metal.

so, no of moles of Aluminium = no of moles of iron

or, weight of Aluminium/atomic weight of Al = weight of iron/atomic weight of iron

or, weight of aluminium/27 = 1120/56

or, weight of aluminium = 1120 × 27/56 = 540 grams.

hence, 540g of aluminium required getting 1120g of iron by given reaction.

Answer 2

Answer:

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