Question

calculate the amount of ammonia formed when 56g of nitrogen reacts with hydrogen ( Atomic mass of N=14, H=1 )​

Answer 1

N2+3H2≈2NH3

Moles of N2=56/28=2moles

Compare this moles with moles of NH3

moles of NH3 =2*2=4moles

mass of NH3=4*17=68g