Question

Calculate the amount of benzoic acid (C6H5COOH) required

Answer 1

Putting the given values in above equation,we get

0.15 = (mole of benzoic acid / 250) x 1000

Or

moles of benzoic acid  = (0.15 x 250) / 1000

= 0.0375 mol of benzoic acid

Also molecular mass of benzoic acid  (C6H5COOH)

= 7 × 12 + 6 × 1 + 2 × 16

= 122 g/mol

Therefore amount of benzoic acid = 0.0375 x 122 = 4.575 g

Answer 2

Explanation:

(12×6)+(1×5)+(12)+(12)+(1)

72+5+12+12+1

102u