calculate the amount of calcium oxide produced by the de composition of 20 g of calcium carbonate
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1 mol CaCO₃=100g
0.2 mol CaCO₃= 20g
CaCO₃→CaO+CO₂
So all products will be 0.2 mol
Mass of 0.2 mol CaO=0.2*(40+16)
=0.2*56
=11.2g
0.2 mol CaCO₃= 20g
CaCO₃→CaO+CO₂
So all products will be 0.2 mol
Mass of 0.2 mol CaO=0.2*(40+16)
=0.2*56
=11.2g
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