Question

calculate the amount of cao in kg that can be produced by heating 200kg of limestone by heating 90% pure caco3. NO SPAM.I NEED STEP WISE ANSWER WITH EASY STEPS.

Answer 1

Given :

• heating 200 kg of limestone
• heating 90% pure $\sf{CaCo_3}$

To find :

• calculate the amount of cao in kg

solution :

200 kg of 90% pure means,

$\implies$ 90/100 x 200 = 180 kg

$\sf{CaCo_3}$ ⠀$\xrightarrow{\quad \Delta \quad}$ ⠀⠀⠀⠀CaO ⠀+ ⠀ $\sf{Co_2}$

(40 + 12 + 3 x 16) ⠀ (40 + 16)

100 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ 56

180 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀W

100 g of $\sf{CaCo_3}$ on heating gives 56 gram of lime

180000 g of $\sf{CaCo_3}$ on heating will give lime

$\implies$ $\Large\sf\frac{56\: x\: 180000}{100}$

$\implies$ 100.8 kg

$\implies$ the amount of CaO is 100.8kg

Answer 2

200kg of 90% pure CaCo3 = 90/100×200

= 180 kg

CaCo3 → Cao + Co2

(40+12+3×16) (40+16)

100 56

180 W

100g of CaCo3 on heating gives 56g of lime,

180000g of CaCo3 on heating will give

56×180000/100 = 100.8kg

Amount of Cao is 100.8 kg

Hope it helps!!

Thank you ✌️