calculate the amount of carbon dioxide produced by the reaction of 32g of methane and 32g of oxygen
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CH4+2O2——→CO2+2H2O
FROM THE ABOVE EQUATION IT IS CLEAR THAT 1 MOLE OF OXYGEN WILL REACT WITH 2 MOLES OF OXYGEN TO PRODUCE 1 MOLE OF CARBON-DIOXIDE.
SO IF 1 MOLE (16 GMS) METHANE WILL REACT WITH EXCESS OXYGEN WE WILL GET 1 MOLE OF CARBON-DIOXIDE (44 GMS).
IF 32 GMS OF METHANE REACTS WITH EXCESS OXYGEN,THEN 2 MOLES (88 GMS) OF CARBON-DIOXIDE WILL BE FORMED.
IF THE 32 GMS OF OXYGEN REACTS WITH METHANE, THEN ONLY 0.5 MOLE OF METHANE WILL REACT TO GIVE 0.5 MOLE (22 GMS) OF CARBON-DIOXIDE.
FROM THE ABOVE EQUATION IT IS CLEAR THAT 1 MOLE OF OXYGEN WILL REACT WITH 2 MOLES OF OXYGEN TO PRODUCE 1 MOLE OF CARBON-DIOXIDE.
SO IF 1 MOLE (16 GMS) METHANE WILL REACT WITH EXCESS OXYGEN WE WILL GET 1 MOLE OF CARBON-DIOXIDE (44 GMS).
IF 32 GMS OF METHANE REACTS WITH EXCESS OXYGEN,THEN 2 MOLES (88 GMS) OF CARBON-DIOXIDE WILL BE FORMED.
IF THE 32 GMS OF OXYGEN REACTS WITH METHANE, THEN ONLY 0.5 MOLE OF METHANE WILL REACT TO GIVE 0.5 MOLE (22 GMS) OF CARBON-DIOXIDE.
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