Calculate the amount of carbon dioxide that could be produced when(1) 1 mole of carbon is burnt in air (2) 1 mole of carbon is burnt in 16g of dioxygen (3) 2 mole of carbon are burnt in 16g dioxygen With steps plz
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The chamical equation is:-
C + O2 = CO2
1) when 1 mole of carbon is burnt in 1 mole ( 32g) of air ( dioxygen) , than according to chamical equation 1 mole of carbon dioxide is produced.
2) 32g of Oxigen upon heating gives Co2 = 44g
1 g of oxigen upon heating gives CO2= 44/32
therefore, 16 g of oxigen upon heating gives CO2= 44/ 32*16 = 22 g .
3) According to the question , only 16 g of dioxygen is available . it is a limiting reacent . Thus, 16 g of dioxygen can combine with 0.5 mole of carbon to give 22 g of CO2 ......i hope it helps you
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C + O2 = CO2
1) when 1 mole of carbon is burnt in 1 mole ( 32g) of air ( dioxygen) , than according to chamical equation 1 mole of carbon dioxide is produced.
2) 32g of Oxigen upon heating gives Co2 = 44g
1 g of oxigen upon heating gives CO2= 44/32
therefore, 16 g of oxigen upon heating gives CO2= 44/ 32*16 = 22 g .
3) According to the question , only 16 g of dioxygen is available . it is a limiting reacent . Thus, 16 g of dioxygen can combine with 0.5 mole of carbon to give 22 g of CO2 ......i hope it helps you
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enormous010:
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