Question

Calculate the amount of carbon dioxide that could be produced when 1 mole of carbon is burnt in the year second one mole of carbon is burnt in 16 gram of dioxygen third 2 moles of carbon are burnt in 16 gram of diopters

Answer 1

The chemical equation for the reaction is:

 C(s)       +    O2(g)      =       CO2(g)

1 mole         1 mole            1 mole

                   (32 g)         (44 g)

i) when 1 mole of carbon is burnt in 1 mole(32 g) of air(dioxygen) ,then according to chemical equation (1) 1mole(44 g) of carbon dioxide is produced.

 ii) 32g of Oxygen upon heating gives CO2 = 44g

1 g of Oxygen upon heating gives CO2 = 44/32

 Therefore 16 g of Oxygen upon heating gives CO2 = 44/32*16 = 22 g

(iii) According to the question, only 16 g of dioxygen is available. It is a limiting reactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.

Answer 2

Molecular weight of CO₂

= molecular weight of carbon + molecular weight of dioxygen

= 12g + 32g = 44g

i.e 1 mole of carbon(6g) and 1 mole of dioxygen (32 g ) produce 44 g of carbon dioxide

then 1 mole of carbon burnt with 16 g of oxygen , it will produce 44× 16 /32 = 22 g of CO₂ .

so when 2 mole of carbon burnt with 16 g of oxygen , it will produce 22*2 g of CO₂

i.e 44g of CO₂ will be generated.