Question

calculate the amount of carbon dioxide that could be produced when(1) 1 mole of carbon is burnt in air (2) 1 mole of carbon is burnt in 16g of dioxygen (3) 2 mole of carbon are burnt in 16g dioxygen.

Answer 1

1. when 1 mole of carbon is burnt in 1 mole of air then according to chemical equation 1 mole of carbon is produced

2. 32 get of oxygen upon heating gives CO2=44g
1g of oxygen upon heating gives CO2 =44/32

Therefore 16 get of oxygen upon heating gives CO2 = 44/32*16=22g

3. according to the question only 16th of dioxygen is avaliable. it is a reactant .thus, 16 get can combine with only 0.5 mole of carbon to give 22g of carbon dioxide

Answer 2

Molecular weight of CO₂

= molecular weight of carbon + molecular weight of dioxygen

= 12g + 32g = 44g

i.e 1 mole of carbon(6g) and 1 mole of dioxygen (32 g ) produce 44 g of carbon dioxide

then 1 mole of carbon burnt with 16 g of oxygen , it will produce 44× 16 /32 = 22 g of CO₂ .

so when 2 mole of carbon burnt with 16 g of oxygen , it will produce 22*2 g of CO₂

i.e 44g of CO₂ will be generated.