Question

Calculate the amount of carbondioxide that could be produced when
1) 1 mole of carbon is burnt in air
2)1 mole of carbon is burnt in 16 g of O2
3)2 moles of carbon are burnt in 16 g of O2

Answer 1

it's a stoichiometry easy question

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Answer 2

(i) 1 mole of carbon is burnt in air.

C + O2 ⇒ CO2

1 mole of carbon reacts with 1 mole of O2 to form one mole of CO2.

Calculating Molar Mass Of Carbon Dioxide:

= 12 + 16 * 2

= 12 + 32

= 44 grams

Therefore, the Amount of CO2 produced is 44 grams.

(ii) 1 mole of carbon is burnt in 16 g of O2.

1 mole of carbon burnt in 32 grams of O2 it forms 44 grams of CO2

Therefore, 16 grams of O2 will form  $\frac{44*16}{32}$

= 22 grams of CO2

Therefore, the Amount of CO2 produced in this case is 22 grams.

(iii) 2 moles of carbon are burnt in 16 g of O2.

Since oxygen is the limiting reactant here, the 16g (0.5 mole) of O2 will react with 6g of carbon (0.5 mole) to form 22 g of carbon dioxide. The remaining 18g of carbon (1.5 mol) will not undergo combustion.

Here, in this case also it will form 22 grams of CO2.