calculate the amount of CH4 present in 2.24 L of CH4 at NTP?
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Answered by
5
1 mol of any gas contains 22.4 L
1 mol of CH4 weighs (12+4)= 16 g
so 2.24 L of CH4 will weigh 1.6 g
HOPE IT HELPS!!
1 mol of CH4 weighs (12+4)= 16 g
so 2.24 L of CH4 will weigh 1.6 g
HOPE IT HELPS!!
Answered by
0
1 mole or 16 grams of CH₄
GIVEN
Volume of CH₄ present = 22.4 L at NTP
TO FIND
Amount of CH₄ present.
SOLUTION
We can simply solve the above problem as follows;
We know that volume of 1 mole of any gas at NTP = 22.4L
Now,
Volume of CH₄ gas present at NTP = 22.4 L
Therefore,
Aqmount of CH₄ gas present = 1 mole
We know that,
1 mole of substance = Molar mass of the substance.
Molar mass of CH₄ = 12 + 4(1) = 16 grams
Hence, 1 mole or 16 grams of CH₄
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