Question

calculate the amount of charge flowing in 2 minutes in a wire of resistance 10 ohm when a potential of 20 v is applied between its ends

Answer 1

Hey mate, here is your answer.
R = 10 ohm
V = 20v

Therefore, by using the formula,
V = i×R
20 = i×10
So, i = 20/10
i = 2A

t = 2 minutes
i = 2A
Therefore, by i = q/t
2 = q / 2
q = 2×2 = 4 coulomb
Hope it will help you.

Answer 2

Answer:

240 C

Explanation:

R=10 ohm

V=20 V

V=iR

20=i*10

i=20/10

i=2 A

t=2 minutes (120 sec)

i=2 A

i=q/t

2=q/120

q=120*2

q= 240 C