calculate the amount of charge that would flow in 2 hours through an element of an electric bulb drawing a current of 0.35 MA
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A= Q/t
0.35×10^-3= charge /2 hr.
charge = 0.35×10^-3. × 2×60×60
=2.52 C
0.35×10^-3= charge /2 hr.
charge = 0.35×10^-3. × 2×60×60
=2.52 C
alishaagra99:
thnx
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I=Q/T
Q=IT
TIME=7200secs
I=0.25A
Q=7200*0.25
Q=1800Coloumb
Q=IT
TIME=7200secs
I=0.25A
Q=7200*0.25
Q=1800Coloumb
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