Question

calculate the amount of charge
that would flow in 2 hours
through
electrue bulb drawing a current of 0.35A
​

Answer 1

Answer:

1 hour =60×60 sec

2 hour = 2 ×60×60=3600×2=7200

i=q/t

q=it

q=.35×7200=2520 coulomb

Answer 2

Refer to the image for the solution