Calculate the amount of charge that would flow in 2 hours through an element of an electric bulb drawing a current of 0.25 a
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12
since Q = i×t
therefore Q = 0.25 × 7200
= 1800c.
t = 2hours= 7200 secs
therefore Q = 0.25 × 7200
= 1800c.
t = 2hours= 7200 secs
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2
Answer:
Q = 1800 C.
Explanation:
Q = I x T
= 0.25 x 7200 s
= 1800 C
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