Calculate the amount of charge that would flow in 3 hour through an element of an electric bulb drawing a current of 5 A.
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Answered by
0
Answer:
Explanation:
Time ‘t’ = 2 hours = 2 × 60 × 60s
t = 7200s
I = 2.5A
Amount of charge,
Q = I × t
= 2.5 × 7200
Q = 18000C
Answered by
0
Answer:
54000 coulomb
Explanation:
1 Ampere = 1 Coulomb/sec
so 5A means 5 Coulomb charge is flowing per second
Total time = 3 hrs = 3*60*60 sec = 10800 sec
Total charge = charge flowing per second * total time in second
Total charge = 5*10800 = 54000 Coulomb
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