Calculate the amount of charge that would flow in
two hours through the filament of an electric bulb drawing a current of 0.25A.
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Answered by
0
Explanation:
As charge, Q=current(I)×time(t),Q=(2.5A)(2×3600s)=1800C.
May it will help you
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1
Two hours=7200s
I=0.25A
I=Q/t
Q=It
Q=0.25*7200
Q=225C
I=0.25A
I=Q/t
Q=It
Q=0.25*7200
Q=225C
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