Question

calculate the amount of Cl2 produced bye the treatment of 1.72 gram of MnOw with HCL​

Answer 1

Answer:

don't know sorry friend

Explanation:

pls sorry............

Answer 2

Answer:

Mass of Cl2 = 1.42 gm

Explanation:

4HCl+ MnO2 = Cl2+ MnCl2+ 2H2O

Molar mass MnO2= 87

Given weight of MnO2= 1.72

:. n(MnO2)= w/M = 1.72/87 = 0.02

as, n(MnO2)= n(Cl2)=0.02

Thus, Moles of Cl2 = 0.02= W/M'= W/71

:. Mass of Cl2 = 1.42 gm