Calculate the amount of CO2 in grams formed in the reaction when 100 g of ethane reacts with 50 g of
oxygen according to chemical reaction : 2C2H6 + 7O2 → 4CO2 + 6H2O.
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Answer:
The answer is 38.72 grams of CO2 is produced
Explanation:
firstly we have to convert 100g of ethane int moles and that is 100/30(molar mass of ethane)
=it comes 3.33 moles
and 50/32(molar mass of o2 gas)
=it comes 1.56 moles
The question is of limiting reagent,and here the limiting reagent is o2
so co2 formed is dependent in o2 so
7 moles of o2 gives 4 moles co2
so 1 mole o2 gives 4/7 moles co2
and 1.56 moles o2 gives 4/7 X 1.56 =0.88moles of co2 gas
and we know that no of moles x molar mass = mass (in grams)
so 0.88 X 44(molar mass of co2)=38.72 grams
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