Question

calculate the amount of co2 liberated when 30g of glucose on complete combustion​

Answer 1

Answer:

Explanation:

C6H12O6 on combustion gives 6moles of CO2 and 6 moles of H20

:- C6H12O6 :-- 6CO2 + 6H2O

and 30 gm of glucose is given in the question so we can easily find the moles of glucose (given mass / molar mass) ~ 30/180 - 1/6 moles

So by equation 1 mole of glucose requiers 6 moles of CO2 so 1/6 moles of glucose required 1 mole of CO2 from mole we can easily find its weight

Mole - given weight/ molar mass

1 -- given weight/ 44

So weight is = 44gm is the ans...