calculate the amount of co2 produced by the combustion of 60 gram of ethane
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Answer: 89.6 L
Explanation:
2C2H6 + 7 O2- 4CO2 + 3H2O
C2H6 = 30amu
moles = 2 moles
So moles of CO2 = 4
At STP Vol of CO2 = 4 X 22.4 = 89.6L
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