Question

Calculate the amount of co2 that could be produced when one mole of carbon is burnt in 16g of o2

Answer 1

$\boxed{\sf{\bold{\Large{\green{C+O_2 \rightarrow CO_2}}}}}$

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Amount of Carbon given = 1 mole

Mass of Carbon given = 12 Grams

Mass of Oxygen Given = 16g

Molar mass of Oxygen = 32 grams

Number of moles of Oxygen will be :-

$=\dfrac{16}{32}\\ \\ \\=0.5\:moles$

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Clearly we know:-

Oxygen is the Limiting Reagent here.

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1 mole of oxygen produces 1 mole of carbondioxide

Therefore:-

0.5 moles of Oxygen will produce 0.5 moles of Carbondioxide

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Mass of CO2 produced will be :-

$=0.5(12+32)\\ \\ \\=0.5(44)\\ \\ \\=22\:Grams$

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Answer 2

$\Large{\mathfrak{\underline{\underline{Answer :-}}}}$

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The balanced reaction of combustion of carbon in dioxygens is:

$\textsf{C(s) + O2(g) => CO2 (g)}\\ </p><p>\textsf{1mole 1mole(32g) 1mole(44g)}$

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(i) In di-oxygen, combustion is complete. Therefore 1 mole of carbon dioxide produced by burning 1 mole of carbon.

(ii) Here, oxygen acts as a limiting reagent as only 16 g of di-oxygen is available. Hence, it will react with 0.5 mole of carbon to give 22 g of carbon dioxide.

(iii) Here again oxygen acts as a limiting reagent as only 16 g of di-oxygen is available. It is a limiting reactant. Thus, 16 g of di-oxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.

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Hope it Helps !!!!