Question

calculate the amount of Cu and br2 produced in 1.5 hour at inert electeodes in a solution of CuBr2 bya 3.5 A current {MM of Br2 is 159.8}.

Answer 1

Answer:

GRam Equivalent = Q /F

GE = I × t /F

F = 96500C

I = 3.5 A

t = 1.5 × 3600. sec

GE = w/eq W

eq W = Mw/nf

nf for Cu = 2

nf for Br = 2

Mw of Cu = 63.5 g

Mw of Br2 = 159.8g

Solution :-

Put Value get Answer

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Mathematics is secondary Matter