Question

calculate the amount of curiosity and br2 produced in 1.5 hrs at inert electrodes in a solution ​

Answer 1

Explanation:

Calculate the amounts of Cu and Br2 produced in 1.0 h at inert electrodes in a solution of CuBr2 by a current of 4.50 A.

MW (Cu) = 63.55 g/mol MW (Br2) = 160 g/mol n = 2 mol e-. Follow the units while remembering calculation string.

Answer 2

Given:

• current mm of br2 is 159.8
• electrodes in a solution of cubr2 are 3.5A

To find: calculate the amount of cu and br2.

Explanation:

as we know that,

the gram equivalent = Q/F

here Q is equal to I × t then,

gram equivalent (GE) = I × t/F

we have values,

                          F = 96500C

                          I = 3.5A

                          t = 1.5 × 3600 sec.

by putting all the values,

                          GE = $3.5$ × $\frac{5400}{96500}$

                          GE = $63.63$

as we know that,

                          GE = w/eq.W

to find the value of eq.W,

                           eq.W = Mw/nf

nf for Cu                       = 2

nf for Br                        = 2

Mw of Cu                      = 63.5g

Mw of Br2                     = 159.8g

eq.W for Cu                  = $\frac{63.5}{2}$ = 31.75

eq.W for Br                   =$\frac{159.8}{2}$ = 79.9

hence cu produced 31.75 and br produced 79.9.